X 4 13x 2 36
Answer by jim_thompson5910(35256)



You lot can put this solution on YOUR website!
Looking at we can come across that the start term is
and the concluding term is
where the coefficients are 1 and 36 respectively.
Now multiply the kickoff coefficient i and the last coefficient 36 to go 36. Now what ii numbers multiply to 36 and add together to the center coefficient -xiii? Let'southward list all of the factors of 36:
Factors of 36:
1,2,3,4,6,9,12,18
-one,-ii,-3,-four,-6,-nine,-12,-xviii ...List the negative factors equally well. This will allow united states to find all possible combinations
These factors pair upwards and multiply to 36
i*36
two*18
iii*12
4*9
6*half dozen
(-1)*(-36)
(-two)*(-18)
(-three)*(-12)
(-iv)*(-ix)
(-6)*(-6)
annotation: remember two negative numbers multiplied together make a positive number
At present which of these pairs add to -13? Lets make a table of all of the pairs of factors we multiplied and run into which two numbers add together to -13
First Number | Second Number | Sum |
---|---|---|
i | 36 | i+36=37 |
ii | 18 | 2+eighteen=20 |
3 | 12 | 3+12=15 |
4 | ix | 4+9=13 |
6 | 6 | 6+6=12 |
-1 | -36 | -1+(-36)=-37 |
-two | -18 | -2+(-18)=-20 |
-iii | -12 | -3+(-12)=-15 |
-4 | -nine | -4+(-ix)=-13 |
-half-dozen | -vi | -6+(-half-dozen)=-12 |
From this list we can see that -iv and -9 add up to -13 and multiply to 36
At present looking at the expression , supervene upon
with
(notice
adds upwardly to
. And then it is equivalent to
)
Now let'due south factor by grouping:
Grouping like terms
Factor out the GCF of
out of the first grouping. Factor out the GCF of
out of the 2d group
Since nosotros take a common term of
, we tin can combine like terms
So factors to
So this also means that factors to
(since
is equivalent to
)
So factors to
-----------------------------
Showtime with the given factorization
Factor
to get
(by use of the divergence of squares)
Gene
to go
(by use of the difference of squares)
------------------------------------------------------------
Reply:
Then completely factors to
Note: the order of the factors does not matter.
Answer by Alan3354(68915)


You can put this solution on YOUR website!
Factor....Need some help
x^four-13x^ii+36
----------------
Information technology volition exist (x^2 + ?)*(x^2 + ?)
The ?'s production will exist 36, and they add upward to -13.
Since it's +36, they have to have the same sign, both Pos or both Neg.
Since they add to -thirteen, they'll have to be both negative.
Consider the factors of 36:
1*36
2*eighteen
iii*12
four*9, and
six*6
They're the same sign, so that add to thirteen. If the were not the same sign, you would look at the differences.
Only 4 and 9 add to 13, so they're it.
It's (10^ii - 4)*(x^2 - ix)
Answer by ankor@dixie-net.com(22666)


You can put this solution on YOUR website!
x^4 - 13x^two + 36
Factor this similar an ordinary quadratic except yous have:
:
:
Note that each factor is the "difference of squares" and can be further factored
(ten^2 - 9) = (10 - iii)(x + 3)
and
(x^2 - 4) = (ten - 2)(ten + 2)
X 4 13x 2 36,
Source: https://www.algebra.com/algebra/homework/Distributive-associative-commutative-properties/Distributive-associative-commutative-properties.faq.question.168695.html
Posted by: millswhimen.blogspot.com
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